Ответ (Неопределённый)
[src]
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| |
| cos(x) | cos(x)
| -------- dx = C + | -------- dx
| cos(2*x) | cos(2*x)
| |
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$${{\sqrt{2}\,\log \left(2\,\sin ^2x+2^{{{3}\over{2}}}\,\sin x+2\,
\cos ^2x+2^{{{3}\over{2}}}\,\cos x+2\right)+\sqrt{2}\,\log \left(2\,
\sin ^2x+2^{{{3}\over{2}}}\,\sin x+2\,\cos ^2x-2^{{{3}\over{2}}}\,
\cos x+2\right)-\sqrt{2}\,\log \left(2\,\sin ^2x-2^{{{3}\over{2}}}\,
\sin x+2\,\cos ^2x+2^{{{3}\over{2}}}\,\cos x+2\right)-\sqrt{2}\,
\log \left(2\,\sin ^2x-2^{{{3}\over{2}}}\,\sin x+2\,\cos ^2x-2^{{{3
}\over{2}}}\,\cos x+2\right)}\over{8}}$$
1
/
|
| cos(x)
| -------- dx
| cos(2*x)
|
/
0
$${{\log \left(2\,\sin ^21+2^{{{3}\over{2}}}\,\sin 1+2\,\cos ^21+2^{
{{3}\over{2}}}\,\cos 1+2\right)}\over{2^{{{5}\over{2}}}}}+{{\log
\left(2\,\sin ^21+2^{{{3}\over{2}}}\,\sin 1+2\,\cos ^21-2^{{{3
}\over{2}}}\,\cos 1+2\right)}\over{2^{{{5}\over{2}}}}}-{{\log \left(
2\,\sin ^21-2^{{{3}\over{2}}}\,\sin 1+2\,\cos ^21+2^{{{3}\over{2}}}
\,\cos 1+2\right)}\over{2^{{{5}\over{2}}}}}-{{\log \left(2\,\sin ^21
-2^{{{3}\over{2}}}\,\sin 1+2\,\cos ^21-2^{{{3}\over{2}}}\,\cos 1+2
\right)}\over{2^{{{5}\over{2}}}}}$$
=
1
/
|
| cos(x)
| -------- dx
| cos(2*x)
|
/
0
$$\int\limits_{0}^{1} \frac{\cos{\left(x \right)}}{\cos{\left(2 x \right)}}\, dx$$