Ответ (Неопределённый)
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| x*sin(x) x sin(x)
| -------- dx = C + --------- - --------
| 3 2 2*cos(x)
| cos (x) 2*cos (x)
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$${{\left(2\,x\,\sin \left(2\,x\right)-\cos \left(2\,x\right)-1
\right)\,\sin \left(4\,x\right)+\left(\sin \left(2\,x\right)+2\,x\,
\cos \left(2\,x\right)\right)\,\cos \left(4\,x\right)+4\,x\,\sin ^2
\left(2\,x\right)-\sin \left(2\,x\right)+4\,x\,\cos ^2\left(2\,x
\right)+2\,x\,\cos \left(2\,x\right)}\over{\sin ^2\left(4\,x\right)+
4\,\sin \left(2\,x\right)\,\sin \left(4\,x\right)+\cos ^2\left(4\,x
\right)+\left(4\,\cos \left(2\,x\right)+2\right)\,\cos \left(4\,x
\right)+4\,\sin ^2\left(2\,x\right)+4\,\cos ^2\left(2\,x\right)+4\,
\cos \left(2\,x\right)+1}}$$
4 2 3
1 tan (1/2) 2*tan(1/2) 2*tan (1/2) 2*tan (1/2)
----------------------------- + ----------------------------- - ----------------------------- + ----------------------------- + -----------------------------
2 4 2 4 2 4 2 4 2 4
2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2)
$${{2\,\sin 2\,\sin 4}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+
\left(4\,\cos 2+2\right)\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1
}}-{{\cos 2\,\sin 4}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+\left(
4\,\cos 2+2\right)\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1}}-{{
\sin 4}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2
\right)\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1}}+{{\sin 2\,
\cos 4}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2
\right)\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1}}+{{2\,\cos 2\,
\cos 4}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2
\right)\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1}}+{{4\,\sin ^22
}\over{\sin ^24+4\,\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2\right)
\,\cos 4+4\,\sin ^22+4\,\cos ^22+4\,\cos 2+1}}-{{\sin 2}\over{\sin ^
24+4\,\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2\right)\,\cos 4+4\,
\sin ^22+4\,\cos ^22+4\,\cos 2+1}}+{{4\,\cos ^22}\over{\sin ^24+4\,
\sin 2\,\sin 4+\cos ^24+\left(4\,\cos 2+2\right)\,\cos 4+4\,\sin ^22
+4\,\cos ^22+4\,\cos 2+1}}+{{2\,\cos 2}\over{\sin ^24+4\,\sin 2\,
\sin 4+\cos ^24+\left(4\,\cos 2+2\right)\,\cos 4+4\,\sin ^22+4\,
\cos ^22+4\,\cos 2+1}}$$
=
4 2 3
1 tan (1/2) 2*tan(1/2) 2*tan (1/2) 2*tan (1/2)
----------------------------- + ----------------------------- - ----------------------------- + ----------------------------- + -----------------------------
2 4 2 4 2 4 2 4 2 4
2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2) 2 - 4*tan (1/2) + 2*tan (1/2)
$$- \frac{2 \tan{\left(\frac{1}{2} \right)}}{- 4 \tan^{2}{\left(\frac{1}{2} \right)} + 2 \tan^{4}{\left(\frac{1}{2} \right)} + 2} + \frac{\tan^{4}{\left(\frac{1}{2} \right)}}{- 4 \tan^{2}{\left(\frac{1}{2} \right)} + 2 \tan^{4}{\left(\frac{1}{2} \right)} + 2} + \frac{2 \tan^{3}{\left(\frac{1}{2} \right)}}{- 4 \tan^{2}{\left(\frac{1}{2} \right)} + 2 \tan^{4}{\left(\frac{1}{2} \right)} + 2} + \frac{2 \tan^{2}{\left(\frac{1}{2} \right)}}{- 4 \tan^{2}{\left(\frac{1}{2} \right)} + 2 \tan^{4}{\left(\frac{1}{2} \right)} + 2} + \frac{1}{- 4 \tan^{2}{\left(\frac{1}{2} \right)} + 2 \tan^{4}{\left(\frac{1}{2} \right)} + 2}$$