Интеграл cos(x)/sqrt(x) d{x}
Решение
Ответ (Неопределённый)
[src]
/
| / ___ ___\
| cos(x) ___ ____ |\/ 2 *\/ x |
| ------ dx = C + \/ 2 *\/ pi *C|-----------|
| ___ | ____ |
| \/ x \ \/ pi /
|
/
$$-{{\sqrt{\pi}\,\left(\left(\sqrt{2}\,i-\sqrt{2}\right)\,
\mathrm{erf}\left({{\left(\sqrt{2}\,i+\sqrt{2}\right)\,\sqrt{x}
}\over{2}}\right)+\left(\sqrt{2}\,i+\sqrt{2}\right)\,\mathrm{erf}
\left({{\left(\sqrt{2}\,i-\sqrt{2}\right)\,\sqrt{x}}\over{2}}\right)
+\left(-\sqrt{2}\,i-\sqrt{2}\right)\,\mathrm{erf}\left(\sqrt{-i}\,
\sqrt{x}\right)+\left(\sqrt{2}\,i-\sqrt{2}\right)\,\mathrm{erf}
\left(\left(-1\right)^{{{1}\over{4}}}\,\sqrt{x}\right)\right)}\over{
8}}$$
/ ___ \
___ ____ |\/ 2 |
\/ 2 *\/ pi *C|------|*Gamma(1/4)
| ____|
\\/ pi /
---------------------------------
4*Gamma(5/4)
$$-{{\sqrt{\pi}\,\left(\left(\sqrt{2}\,i-\sqrt{2}\right)\,
\mathrm{erf}\left({{\sqrt{2}\,i+\sqrt{2}}\over{2}}\right)+\left(
\sqrt{2}\,i+\sqrt{2}\right)\,\mathrm{erf}\left({{\sqrt{2}\,i-\sqrt{2
}}\over{2}}\right)+\left(-\sqrt{2}\,i-\sqrt{2}\right)\,\mathrm{erf}
\left(\sqrt{-i}\right)+\left(\sqrt{2}\,i-\sqrt{2}\right)\,
\mathrm{erf}\left(\left(-1\right)^{{{1}\over{4}}}\right)\right)
}\over{8}}$$
=
/ ___ \
___ ____ |\/ 2 |
\/ 2 *\/ pi *C|------|*Gamma(1/4)
| ____|
\\/ pi /
---------------------------------
4*Gamma(5/4)
$$\frac{\sqrt{2} \sqrt{\pi} C\left(\frac{\sqrt{2}}{\sqrt{\pi}}\right) \Gamma\left(\frac{1}{4}\right)}{4 \Gamma\left(\frac{5}{4}\right)}$$
Данные примеры также можно применять при вводе верхнего и нижнего предела интегрирования.